so, write it clearly:
limit as x->1 of (x-1)/(√x - 2x)
I see no problem here, since √x - 2x -> -1, which is not zero.
(x-1)/(√x-2x) -> 0
Apparently I have it wrong, but cannot see an easy way to massage it into something which -> 0/0
Anyway, try l'Hospital's Rule if you get a 0/0 limit.
Evaluate the limit of x-1 / square root of x - 2x as x approaches to 1.
NOTE: 2X does not belong to the square root.
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