evaluate the limit:

lim cos(x + pi/2)/x
x->0

1 answer

cos(x+pi/2)
= cosx cos pi/2 - sinx sin pi/2
= 0 - sinx
= -sinx

so
limit cos(x+pi/2)/x as x----> o
= lim -sinx/x , x ---> 0
= -1

using the fact that lim sinx/x = 1
Similar Questions
    1. answers icon 0 answers
    1. answers icon 9 answers
  1. Evaluate the limit:Limit as x approaches 6 from the right: Sq.root of (x - 6). I know the limit is 0, but how do I show this?
    1. answers icon 0 answers
  2. Evaluate limit, x -> a, [(x + 4a)^2 - 25a^2] / [x - a]My work: = limit, x -> a, (x^2 + 8ax + 16a^2 - 25a^2) / (x - a) = limit, x
    1. answers icon 1 answer
more similar questions