I got
(1/4) (ln(x-2) - ln(x+2) ) + c
how did your x-2 from the original denominator turn into 2-x)
I used partial fractions
Evaluate the integral.
integral 1/((x-2)(x+2))
Note: Use an upper-case "C" for the constant of integration.
I keep getting 1/4[log(2-x)-log(x+2)]+C and the system is saying its wrong... Please help!
2 answers
Ty