Use the substitution:
u=e^(7x)
then
du = 7e^(7x)dx
and the integral
I=∫e^(7x)/(e^(14x)+16)dx
=(1/7)∫du/(u²+16)
which is a standard form that for arctan
=(1/7)(1/4)tan-1(u/4)
Back-substitute u=e^(7x) into the expression to get the answer in terms of x.
Evaluate the indefinite integral.
(e^7x)/(e^14x+16)dx
1 answer
1 answer