How on earth did you get that mess? Just add the separate integrals of 8x and -x^2.
The answer is
4x^2 - (x^3)/3
To verify, differentiate it and see if you get 8x-x^2 back again.
Evaluate the indefinite integral: 8x-x^2.
I got this but I the homework system says its wrong:sqrt((-x-8)x)/(2*sqrt(x-8)*sqrt(x))*(((sqrt(x-8)*(x-4)*sqrt(x))-32*log(sqrt(x-8)+sqrt(x))
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Sorry, it is evaluate the indefinite integral: sqrt(8x-x^2)
2y*y'=x/sqrt(x^2-16)
1 answer