Is the second term (4/7)x or 4/(7x) ?
It makes a big differnece.
Add the separate integrals of the two terms. The indefinite integral of
4/x^5 (4 x^-5) is 4 x^-4/(-4) = -x^(-4)
Evaluate the indefinite integral: ((4/x^5)+(4/7x))dx
1 answer
1 answer