I am guessing you want the derivative of the piecewise-continuous function
f(x) = 2(x^2 + 3|x|) ,
but what does the "1" represent?
If you want the derivative at x=1, you can remove the | | signs
Evaluate the given expression.
d
dx
[2(x2 + 3|x|)]
1
2 answers
For |x|, we have 2 situations.
|x| = x, for x >= 0
|x| = -x, for x < 0
So:
¤ for x>=0:
d/dx (2(x^2 + 3x)) = ?
¤ for x<0:
d/dx (2(x^2 - 3x)) = ?
|x| = x, for x >= 0
|x| = -x, for x < 0
So:
¤ for x>=0:
d/dx (2(x^2 + 3x)) = ?
¤ for x<0:
d/dx (2(x^2 - 3x)) = ?