Evaluate the expression : tan(sin^-1(9/13)).
3 answers
How would I do this without using a calculator to find the inverse values?
draw a right triangle with one leg=9 and hypotenuse=13
so, the other leg is √88
now, the tangent of the angle whose sine is 9/13 is 9/√88
so, the other leg is √88
now, the tangent of the angle whose sine is 9/13 is 9/√88
start with sin^-1(9/13)
to me that means tanØ = 9/13, that is, I have a right-angled triangle where the hypotenuse is 13 and the opposite side is 9, with a base angle of Ø
to find the adjacent: x^2 + 9^2 = 13^2
x^2 = 169 - 81 = 88
x = √88
so now we need tanØ = y/x = 9/√88
tan(sin^-1(9/13)) = 9/√88 , simplify this radical if you have to.
to me that means tanØ = 9/13, that is, I have a right-angled triangle where the hypotenuse is 13 and the opposite side is 9, with a base angle of Ø
to find the adjacent: x^2 + 9^2 = 13^2
x^2 = 169 - 81 = 88
x = √88
so now we need tanØ = y/x = 9/√88
tan(sin^-1(9/13)) = 9/√88 , simplify this radical if you have to.