Asked by sammy grl, bro
Evaluate the expression if x=16, y=- 6, and a=2.
2y^2-x/a+12
2y^2-x/a+12
Answers
Answered by
sammy grl, bro
Try again
Answered by
GPT-4o mini
To evaluate the expression \( 2y^2 - \frac{x}{a} + 12 \) given \( x = 16 \), \( y = -6 \), and \( a = 2 \), we can follow these steps:
1. Calculate \( 2y^2 \).
2. Calculate \( \frac{x}{a} \).
3. Combine the results with the constant 12.
Let's go step by step.
1. Calculate \( 2y^2 \):
\[
y^2 = (-6)^2 = 36
\]
\[
2y^2 = 2 \times 36 = 72
\]
2. Calculate \( \frac{x}{a} \):
\[
\frac{x}{a} = \frac{16}{2} = 8
\]
3. Now substitute these values back into the expression:
\[
2y^2 - \frac{x}{a} + 12 = 72 - 8 + 12
\]
4. Perform the addition and subtraction:
\[
72 - 8 = 64
\]
\[
64 + 12 = 76
\]
Thus, the value of the expression is \( \boxed{76} \).
1. Calculate \( 2y^2 \).
2. Calculate \( \frac{x}{a} \).
3. Combine the results with the constant 12.
Let's go step by step.
1. Calculate \( 2y^2 \):
\[
y^2 = (-6)^2 = 36
\]
\[
2y^2 = 2 \times 36 = 72
\]
2. Calculate \( \frac{x}{a} \):
\[
\frac{x}{a} = \frac{16}{2} = 8
\]
3. Now substitute these values back into the expression:
\[
2y^2 - \frac{x}{a} + 12 = 72 - 8 + 12
\]
4. Perform the addition and subtraction:
\[
72 - 8 = 64
\]
\[
64 + 12 = 76
\]
Thus, the value of the expression is \( \boxed{76} \).
Answered by
GPT-4o mini
Let's go through the evaluation of the expression \( 2y^2 - \frac{x}{a} + 12 \) again, step by step, using \( x = 16 \), \( y = -6 \), and \( a = 2 \).
1. **Calculate \( y^2 \):**
\[
y^2 = (-6)^2 = 36
\]
2. **Calculate \( 2y^2 \):**
\[
2y^2 = 2 \times 36 = 72
\]
3. **Calculate \( \frac{x}{a} \):**
\[
\frac{x}{a} = \frac{16}{2} = 8
\]
4. **Combine the results:**
\[
2y^2 - \frac{x}{a} + 12 = 72 - 8 + 12
\]
5. **Perform the operations:**
- First, do the subtraction:
\[
72 - 8 = 64
\]
- Then, add 12:
\[
64 + 12 = 76
\]
Thus, the correct evaluated value of the expression is \(\boxed{76}\).
If there’s a different method or aspect you’d like me to consider, please let me know!
1. **Calculate \( y^2 \):**
\[
y^2 = (-6)^2 = 36
\]
2. **Calculate \( 2y^2 \):**
\[
2y^2 = 2 \times 36 = 72
\]
3. **Calculate \( \frac{x}{a} \):**
\[
\frac{x}{a} = \frac{16}{2} = 8
\]
4. **Combine the results:**
\[
2y^2 - \frac{x}{a} + 12 = 72 - 8 + 12
\]
5. **Perform the operations:**
- First, do the subtraction:
\[
72 - 8 = 64
\]
- Then, add 12:
\[
64 + 12 = 76
\]
Thus, the correct evaluated value of the expression is \(\boxed{76}\).
If there’s a different method or aspect you’d like me to consider, please let me know!
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