To evaluate the expression 3r/2-^2 when r=-3 and s=5, we substitute -3 for r:
3(-3)/2-^2 = -9/2-^2
Now, we need to evaluate -9/2. Dividing -9 by 2, we get -4 with a remainder of -1. So -9/2 = -4-1/2.
Therefore, the expression becomes:
-4-1/2-^2
Now let's evaluate ^2:
-4-1/2-^2 = -4-1/2-1/4
To perform the subtraction, we need a common denominator, which is 4. So we can rewrite -1/2 as -2/4:
-4-2/4-1/4
Combining the numerators:
= -6/4 - 1/4
Now, we can subtract:
= -7/4
Evaluate the expression for r=-3 and s=5
3r/2-^2
1 answer