To evaluate the expression \((\frac{1}{4})^{-2}\), we can use the property of exponents that states \(a^{-n} = \frac{1}{a^n}\).
Applying this property, we have:
\[ (\frac{1}{4})^{-2} = \frac{1}{(\frac{1}{4})^2} \]
Next, we calculate \((\frac{1}{4})^2\):
\[ (\frac{1}{4})^2 = \frac{1^2}{4^2} = \frac{1}{16} \]
Now we substitute this back into our expression:
\[ \frac{1}{(\frac{1}{4})^2} = \frac{1}{\frac{1}{16}} = 16 \]
So,
\[ (\frac{1}{4})^{-2} = 16 \]
Thus, the final result is:
\[ \boxed{16} \]