Evaluate the express. nCr

Question

(9 over 6)(6 over 4)(3 over 1)
n 9 6 3
r 6 4 1

I came up with,
[10 over 6!(10-6] [6 over 4(4-2!)
[3 over 1!(1-1)!] from there I so sorry I don't know where to go.
thank you

Answer 1

not sure just what you want.
9C6 = 9C3 = 9*8*7/1*2*3 = 84
6C4 = 6C2 = 6*5/1*2 = 15
3C1 = 3/1 = 3

More formally,
9C6 = 9! / (9-6)!6!
6C4 = 6! / (6-4)!4!
3C1 = 3! / (3-1)!1!

Answer 2

I have know what numbers I will have to multiple

9 6 3
6 4 1 =

Answer 3

I think you are referring to one of the alternate ways to represent a combination
see:
http://laurashears.info/math122/unit5/notation/

Steve found the value of each of your combinations, so just multiply them

84*15*3 = .......

Answer 4

Here is a combinations and permutations calculator
to get permutations, the "Is order important" box should be YES
to get combinations the is order important box is NO

http://www.mathsisfun.com/combinatorics/combinations-permutations-calculator.html

Here you are doing combinations, nCr so the box should be NO