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Evaluate the definite integral.

x sqrt(13 x^2 + 36)dx between (0,1)

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x √(13x^2 +36)dx
u = 13x^2 + 36
between (36, 49)

du= 26x
du/26 = x

1/26 (u)^1/2 du

1/26 *2/3 (u)^3/2 to 36 to 49

1/39[ 49^3/2 -36^3/2]

1/39( 343-216) = 127/39

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