Evaluate tan(tan^-1 (π/3) + (π/4) )

Answer 1

Makes no sense. I mean, tan^-1(π/3) is defined, but it is not one you come across very often. I suspect you meant

tan( (π/3) + (π/4) ) = (tan(π/3)+tan(π/4))/(1 - tan(π/3) tan(π/4))
= (√3 + 1)/(1 - √3 * 1)
= (1+√3)/(1-√3)
= (4+2√3)/(1-3)
= -2-√3

Answer 2

Or, just for fun, maybe you meant
tan(tan^-1(1/3) + tan^-1(1/4))
That would be
(1/3 + 1/4)/(1 - 1/3 * 1/4) = 7/11

Answer 3

tan^-1 mean tan inverse, π/3 or π/4 mean pi/3 + pi/4 respectively

Answer 4

I read that as
tan(tan^-1 [(π/3) + (π/4)] ) , see how important brackets are ?
= tan(tan^-1 [ 7π/12] )
which would simply be
7π/12

just like tan(tan^-1 (1/2) ) = 1/2

Answer 5

yes your are write

Answer 6

this what i got when i try it... tan( tan inverse (180/3+ 180/4) ) tan 89.4543 = 105°. am i right?

Answer 7

NO
π = 3.14159... not 180

whenever you see π floating around in trig problems, you can assume that
they are dealing with radians, not degrees.
If you wish to use your calculator for this question, then
π/3+π/4 = 1.832595....
now with your setting on degrees, press
2ndF tan to get 61.379...
now press tan to get 1.8325.. back again!! ,
which is your π/2+π/4 or 7π/12

try it with setting on RAD, same thing, although you get a different intermediate answer.

try it with setting on GRAD, same thing

So 105° is a silly answer.

Answer 8

thanks