Evaluate log(1022⋅4)

log

(
10
22

4
)
.(1 point)
Responses

log(1022⋅4)=log(22+4)
log

(
10
22

4
)
=
log

(
22
+
4
)
logarithm left parenthesis 10 superscript 22 baseline times 4 right parenthesis equals logarithm left parenthesis 22 plus 4 right parenthesis

log(1022⋅4)=22+log4
log

(
10
22

4
)
=
22
+
log

4
logarithm left parenthesis 10 superscript 22 baseline times 4 right parenthesis equals 22 plus logarithm 4

log(1022⋅4)=log(22⋅4)
log

(
10
22

4
)
=
log

(
22

4
)
logarithm left parenthesis 10 superscript 22 baseline times 4 right parenthesis equals logarithm left parenthesis 22 times 4 right parenthesis

log(1022⋅4)=log22+4

1 answer

To evaluate the logarithm \( \log(10^{22} \cdot 4) \), we can use the properties of logarithms.

The properties we need are:

  1. \( \log(a \cdot b) = \log a + \log b \)
  2. \( \log(a^b) = b \cdot \log a \)

Applying the first property to our expression:

\[ \log(10^{22} \cdot 4) = \log(10^{22}) + \log(4) \]

Now applying the second property to \( \log(10^{22}) \):

\[ \log(10^{22}) = 22 \cdot \log(10) \]

Since \( \log(10) = 1 \):

\[ \log(10^{22}) = 22 \]

Substituting back, we get:

\[ \log(10^{22} \cdot 4) = 22 + \log(4) \]

So the correct evaluation is:

\[ \log(10^{22} \cdot 4) = 22 + \log(4) \]

Among your provided responses, the second one is the correct evaluation:

\[ \log(10^{22} \cdot 4) = 22 + \log(4) \]