Evaluate limit of 3√(x²+7) as x approaches 3

Answer 1

To evaluate the limit of 3√(x²+7) as x approaches 3, we substitute 3 for x and simplify:

3√(3²+7) = 3√16 = 3 x 2 = 6

Therefore, the limit of 3√(x²+7) as x approaches 3 is 6.