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limit ((x^3-8)/(x^2-4)) as x->2
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evaluate lim x^3 -8 divided by x^2 -4 as x approaches 2
3 answers
At a 0/0 singularity such as this, you just take the ratio of derivatives:
(3x^2)/2x = (3/2)*x = 3
That is called L'Hopital's Rule.
(3x^2)/2x = (3/2)*x = 3
That is called L'Hopital's Rule.
(x-2)(x^2+2x+4)
=================
(x-2)(x+2)
(x^2+2x+4)
=================
(x+2)
when x = 2
(4+4+4)
=================
(2+2)
3
=================
(x-2)(x+2)
(x^2+2x+4)
=================
(x+2)
when x = 2
(4+4+4)
=================
(2+2)
3