Evaluate integral e^3x cosh 2x dx.

A.1/2 e^5x + 1/2 e^x + C
B.1/10 e^5x + 1/2e^x + C<<< my answer
C.1/4e^3x + 1/2 x + C
D.1/10 e^5x + 1/5 x + C

1 answer

Lets look at b.

d/dx (1/10 e^5x+ 1/2 e^x + C)
1/2 e^5x + 1/2 e^x

1/2 (e^3x (e^2x+e^-2x))

e^3x (e^2x+e-2x)/2

e^3x cosh2x

yep, you are correct.
Similar Questions
  1. evaluate the integral of(e^3x)(cosh)(2x)(dx) A.(1/2)(e^5x)+(1/2)(e^x)+C B.(1/10)(e^5x)+(1/2)(e^x)+C C.(1/4)(e^3x)+(1/2)(x)+C
    1. answers icon 4 answers
  2. what is the anti-derivative on square root of cosh^2(x)?The square root of cosh^2 x is just cosh x, and the integral (or
    1. answers icon 0 answers
  3. definite integral of (e^(8x))cosh(8x)dx from 0 to 1/16-I substitued the definition of cosh in, i.e. (e^(8x) + e^(-8x)/2 but i
    1. answers icon 1 answer
  4. evaluate (integral) xe^2x dxA. 1/6x^2 e^3x+C B. 1/2xe^2x-1/2e^2x+C C. 1/2xe^2x-1/4e^2x+C D. 1/2x^2-1/8e^4x+C Evaluate (integral)
    1. answers icon 2 answers
more similar questions