I need someone to show me steps. I used wolframalpha and got 40 but don't know how to solve this
Thanks!!!
Evaluate!!!!
integral -10 to 10 ((2e^x)/(sinhx+coshx))dx
Thanks!
2 answers
recall that
sinhx = (e^x-e^-x)/2
coshx = (e^x+e^-x)/2
so,
sinhx+coshx = e^x
2e^x/e^x = 2
sinhx = (e^x-e^-x)/2
coshx = (e^x+e^-x)/2
so,
sinhx+coshx = e^x
2e^x/e^x = 2