Question

Evaluate in
(cuberootof(x+1)/(x-1)).1/(x+1)dx
help plz

Answer 1

For the life of me, I cannot decipher your expression

Answer 2

I suspect a typo. Wolframalpha indicates that it cannot be done with elementary functions:

http://www.wolframalpha.com/input/?i=integral+%28%28x%2B1%29%2F%28x-1%29%29^%281%2F3%29%2F%28x%2B1%29dx

If I got it wrong, and only the (x+1) is in the cube root, it can then be done, but not easily:

http://www.wolframalpha.com/input/?i=integral+%28x%2B1%29^%281%2F3%29%2F%28%28x-1%29%28x%2B1%29%29dx

Answer 3

Thanks for figuring out what was meant. I just threw up my hands in frustration.