10π/3 - 2π = 3π/2
then see
http://www.jiskha.com/display.cgi?id=1307390418
Evaluate (if possible) the sine,cosine, and tangent of the angle
10pi/3
2 answers
(10pi/3)rad * (1/2pi)rev/rad = 5/3 =
1 2/3 rev.
2/3 rev * 360deg/rev = 240 deg.
sin(240) = -0.8660 = -(sqrt3)/2.
cos(240) = -0.50 = -1/2.
tan(240) = 1.732 = sqrt3.
240 deg. = 4pi/3 rad.
1 2/3 rev.
2/3 rev * 360deg/rev = 240 deg.
sin(240) = -0.8660 = -(sqrt3)/2.
cos(240) = -0.50 = -1/2.
tan(240) = 1.732 = sqrt3.
240 deg. = 4pi/3 rad.