Evaluate exactly, using the Fundamental Theorem of Calculus:

Question

∫^s_06e^xdx=

Answer 1

By the Fundamental Theorem of Calculus, we have:

∫^s_06e^xdx = [e^x]6^s

To evaluate this, we substitute s and 6 into the expression and subtract:

[e^s] - [e^6]

Therefore, the exact value of the integral is:

e^s - e^6