evaluate 4x^2(2x+x^3y)+x^y for x = 5 and y=0
Evaluate 4 (x/5)^2+3 when c =20
4 answers
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4x^2(2x+x^3y)+x^y = 8x^3 + (4x^5)y + x^y
When multiplying/dividing, exponents are added/subtracted respectively.
Anything to the zero power = 1
4x^5 * zero = zero
So you are left with 8x^3 +1 = ?
When multiplying/dividing, exponents are added/subtracted respectively.
Anything to the zero power = 1
4x^5 * zero = zero
So you are left with 8x^3 +1 = ?
evaluate 4x^2(2x+x^3y)+x^y for x = 5 and y=0
4x^2(2x+x^3y)+x^y
= 4(5^2)(10 + 5^0) + 5^0
= 100( 10 + 1) + 1 , .............. anything^0 = 1
= 1100
4x^2(2x+x^3y)+x^y
= 4(5^2)(10 + 5^0) + 5^0
= 100( 10 + 1) + 1 , .............. anything^0 = 1
= 1100
1 answer