Evaluate:20142015×20152014-20142014×20152015
4 answers
My answer is 10,000 after a lot of calculation
let a=20142014
then 20142015 = a+1
then 20152015 = a + 1 + 1000 = a+1001
then 20152014 = a+1000
20142015×20152014 – 20142014 ×20152015
= (a+1)(a+1000) - a(a+1001)
= a^2 + 1001a + 1000 - a^2 - 1001a
= 1000
without any calculation
then 20142015 = a+1
then 20152015 = a + 1 + 1000 = a+1001
then 20152014 = a+1000
20142015×20152014 – 20142014 ×20152015
= (a+1)(a+1000) - a(a+1001)
= a^2 + 1001a + 1000 - a^2 - 1001a
= 1000
without any calculation
just noticed I left out a zero
let a=20142014
then 20142015 = a+1
then 20152015 = a + 1 + 10000 = a+10001
then 20152014 = a+10000
20142015×20152014 – 20142014 ×20152015
= (a+1)(a+10000) - a(a+10001)
= a^2 + 10001a + 10000 - a^2 - 10001a
= 10000
without any calculation
let a=20142014
then 20142015 = a+1
then 20152015 = a + 1 + 10000 = a+10001
then 20152014 = a+10000
20142015×20152014 – 20142014 ×20152015
= (a+1)(a+10000) - a(a+10001)
= a^2 + 10001a + 10000 - a^2 - 10001a
= 10000
without any calculation
You are great Reiny.