Evaluate 2/(1+J4)^2

Question

I got as far as:
(1+j4)^2=(1+j4)(1+j4)=1+j4+j4+j4^2=1+J24

OR

(1+j4)^2 (/2)

=(0.25+j)(0.25+j)=0.0625+j+j+j^2
=0.0625+j+j-0.0625=J^2

I think it can be take further. but im not sure i'm right.

Answer 1

NVM i think i've done it. I simplified to -2(15+8J)/-289

correct if i'm wrong please!

Answer 2

The bottom is +289