Euchre uses only 9’s, 10’s, Jacks, Queens, KIngs and aces. What is the probability that a 5 card hand will have either both red jacks or both black jacks?

Answer 1

24 cards in all, so
P(both red) = P(both black) = 1/12 * 1/23
so, ...

Answer 2

So there are only 24 cards
number of 5 card hands = C(24,5) = ...
number containing both red Jacks = C(22,3) = ...
number containing both black jacks = C(22,3) =
number of containing all 4 jacks = C(20,1) = ....

number containing either both 2 black or 2 red Jacks
= C(22,3) + C(22,3) - C(10,1) = ..... **

prob of your stated event = **/C(24,5) = ....

Answer 3

Oops. Go with Reiny. My calculations were based on drawing only two cards.