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Ethylene glycol has a specific heat of 0.578 cal/(g×°C). If 23.2 g of ethylene glycol absorbs 75.6 cal of heat energy, what will the temperature increase be?

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q = mass x specific heat x (Tfinal-Tinitial)
75.6 = 23.3 x 0.578 x delta T.
Solve for delta T.

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