heat = q = mass x dHvap.
q = mols ethyl chloride x dHvap
mols ethyl chloride = grams/molar mass = 20.0/64.5 = approx 0.31
q = 0.31 mol x 26.4 kJ/mol = ? kilojoules.
Ethyl chloride, C 2 H 5 Cl, is used as a local anesthetic. It works by cooling tissue as it vaporizes; its heat of vaporization is 26.4 kJ/mol. How much heat could be removed by 20.0 g of ethyl chloride?
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