To determine how many molecules of ethanol (C₂H₆O) are produced in the reaction between ethylene (C₂H₄) and water (H₂O), we need to analyze the reactants and products in terms of atoms.
The reaction can be represented as follows:
1 C₂H₄ + 1 H₂O → x C₂H₆O
Now let's break down the number of each type of atom on both sides of the reaction:
Reactants:
-
Ethylene (C₂H₄):
- 2 Carbon (C) atoms
- 4 Hydrogen (H) atoms
-
Water (H₂O):
- 0 Carbon (C) atoms
- 2 Hydrogen (H) atoms
- 1 Oxygen (O) atom
Total atoms in reactants:
- Carbon (C): 2 (from C₂H₄)
- Hydrogen (H): 4 (from C₂H₄) + 2 (from H₂O) = 6
- Oxygen (O): 1 (from H₂O)
So, the total number of atoms from the reactants is:
- C: 2
- H: 6
- O: 1
Now, in products, each molecule of ethanol (C₂H₆O) contains:
- 2 Carbon (C) atoms
- 6 Hydrogen (H) atoms
- 1 Oxygen (O) atom
Thus, the reaction would produce 1 molecule of ethanol (C₂H₆O).
In conclusion, the number of molecules of ethanol produced in the reaction is 1 molecule.