Get the Limiting Reactant of your reaction,
so get the Molar Mass (MM) of C2H4 and H2O from your periodic table
then
1650 g / MM of C2H4 = __ mol
61 g / MM of H2O = __ mol
the least amount of mol will be your Limiting Reactant.
You use the LR to find the max amount of C2H5OH you will get from your reaction
so
LR in mol * MM of C2H5OH = ___ g
divide answer to get your max amt. in kg
Ethanol (C2H5OH) is synthesized for industrial use by the following reaction, carried out at very high pressure.
C2H4(g) + H2O(g) → C2H5OH(l)
What is the maximum amount, in kg, of ethanol that can be produced when 1.65 kg of ethylene (C2H4) and 0.0610 kg of steam are placed into the reaction vessel?
3 answers
*divide answer by 1000 to get max amt in kg
thanks!