etermining Velocity

A graph titled Position versus time for with horizontal axis time (seconds) and vertical axis position (meters). The line runs in 3 straight segments from 0 seconds 0 meters to 4 seconds 12 meters to 6 seconds 12 meters to 12 seconds 0 meters.
Use the graph to determine the velocity between 6 and 12 seconds.

m/s

What was the velocity over the entire trip?

m/s

1 answer

To determine the velocity between 6 and 12 seconds using the provided graph information, we can analyze the position changes during this time interval.

From the data you provided:

  • At 6 seconds, the position is 12 meters.
  • At 12 seconds, the position is 0 meters.

To calculate the velocity \( v \) between these two points, we use the formula for velocity:

\[ v = \frac{\Delta x}{\Delta t} \]

Where:

  • \( \Delta x \) is the change in position (final position - initial position),
  • \( \Delta t \) is the change in time (final time - initial time).

Step 1: Calculate \( \Delta x \) and \( \Delta t \)

  • \( \Delta x = 0 , \text{meters} - 12 , \text{meters} = -12 , \text{meters} \)
  • \( \Delta t = 12 , \text{seconds} - 6 , \text{seconds} = 6 , \text{seconds} \)

Step 2: Calculate the velocity

\[ v = \frac{-12 , \text{meters}}{6 , \text{seconds}} = -2 , \text{m/s} \]

Thus, the velocity between 6 and 12 seconds is -2 m/s.

Overall Velocity

To find the overall velocity for the entire trip, we can calculate the total change in position over the total time taken.

Total Change in Position

  • Initial position at 0 seconds: 0 meters
  • Final position at 12 seconds: 0 meters

So, the total change in position (\( \Delta x \)) for the trip is: \[ \Delta x = 0 , \text{meters} - 0 , \text{meters} = 0 , \text{meters} \]

Total Time

The total time (\( \Delta t \)) for the trip is: \[ \Delta t = 12 , \text{seconds} - 0 , \text{seconds} = 12 , \text{seconds} \]

Overall Velocity Calculation

Using the same velocity formula: \[ v_{\text{overall}} = \frac{\Delta x}{\Delta t} = \frac{0 , \text{meters}}{12 , \text{seconds}} = 0 , \text{m/s} \]

Therefore, the overall velocity of the trip is 0 m/s.