The given equation can be rewritten in terms of a as follows:
a^2 + 32 = 12a + 48
Now, set the equation equal to zero:
a^2 - 12a + 16 = 0
In this resulting equation, the coefficient of the a term is -12 and the constant term is 16.
et a = x^2 + 4. Rewrite the following equation in terms of a and set it equal to zero.
((x^2 + 4)^2) + 32 = 12x^2 + 48
in resulting equation what is the coefficient of the a term? _____. In the resulting equation, what is the constant? _______
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