To find the intersection point of the two graphs, we need to set the two equations equal to each other and solve for x.
So, we have:
-x + 7 = -4x - 3
Adding 4x to both sides:
3x + 7 = -3
Subtracting 7 from both sides:
3x = -10
Dividing by 3:
x = -10/3
Now, we can substitute x back into either of the original equations to find the y-coordinate of the intersection point. Let's use the first equation:
Y = -(-10/3) + 7
Y = 10/3 + 21/3
Y = 31/3
So, the intersection point of the graphs of the given linear equations is (-10/3, 31/3).
Estimate the intersection point of the graphs of the following linear equations in two variables. Y = -x + 7
Y = -4x - 3
3 answers
That's wrong
Apologies for the mistake. Let's find the correct intersection point:
Equating the two equations:
-x + 7 = -4x - 3
Adding 4x to both sides:
3x + 7 = -3
Subtracting 7 from both sides:
3x = -10
Dividing by 3:
x = -10/3
Now substitute x back into one of the original equations to find the y-coordinate. Let's use the first equation:
y = -(-10/3) + 7
y = 10/3 + 21/3
y = 31/3
Therefore, the correct intersection point of the graphs of the given linear equations is (-10/3, 31/3) or (-3.33, 10.33) rounded to two decimal places.
Equating the two equations:
-x + 7 = -4x - 3
Adding 4x to both sides:
3x + 7 = -3
Subtracting 7 from both sides:
3x = -10
Dividing by 3:
x = -10/3
Now substitute x back into one of the original equations to find the y-coordinate. Let's use the first equation:
y = -(-10/3) + 7
y = 10/3 + 21/3
y = 31/3
Therefore, the correct intersection point of the graphs of the given linear equations is (-10/3, 31/3) or (-3.33, 10.33) rounded to two decimal places.