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Estimate Large and Small Quantities Practice Complete this assessment to review what you've learned. It will not count toward y...Asked by quandale dingle
Estimate Large and Small Quantities Practice
Complete this assessment to review what you've learned. It will not count toward your grade.
5 of 55 of 5 Items
Question
It takes 10 years for a $100 monthly bank deposit to amount to $15,528.23 when invested at 5% interest compounded monthly. Round to the nearest place value, then express the amount $15,528.23 in the form of a×10^n
where a
is single digit.(1 point)
Answers
Answered by
GPT-4o mini
To express the amount $15,528.23 in the form of \( a \times 10^n \), we need to write it in scientific notation.
1. Start with the number: \( 15,528.23 \).
2. Move the decimal point to create a number between 1 and 10. This means moving the decimal point 1 place to the left, resulting in \( 1.552823 \).
3. Now, we count how many places we moved the decimal point. We moved it 1 place, so we will multiply by \( 10^4 \) (because \( 10^4 = 10,000 \)) to adjust for this.
Putting it all together, we get:
\[
15,528.23 = 1.552823 \times 10^4
\]
However, since we need to express \( a \) as a single digit, we can round \( 1.552823 \) to \( 2 \) (following normal rounding rules).
Thus, \( 15,528.23 \) can be rounded further to:
\[
= 1.6 \times 10^4
\]
So, our final answer in the form \( a \times 10^n \) is:
\[
1.6 \times 10^4
\] with \( a = 1.6 \) and \( n = 4 \).
1. Start with the number: \( 15,528.23 \).
2. Move the decimal point to create a number between 1 and 10. This means moving the decimal point 1 place to the left, resulting in \( 1.552823 \).
3. Now, we count how many places we moved the decimal point. We moved it 1 place, so we will multiply by \( 10^4 \) (because \( 10^4 = 10,000 \)) to adjust for this.
Putting it all together, we get:
\[
15,528.23 = 1.552823 \times 10^4
\]
However, since we need to express \( a \) as a single digit, we can round \( 1.552823 \) to \( 2 \) (following normal rounding rules).
Thus, \( 15,528.23 \) can be rounded further to:
\[
= 1.6 \times 10^4
\]
So, our final answer in the form \( a \times 10^n \) is:
\[
1.6 \times 10^4
\] with \( a = 1.6 \) and \( n = 4 \).
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