To estimate √53 to the tenths place, we can follow the steps you've outlined.
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Identify perfect squares:
We note that \(7^2 = 49\) and \(8^2 = 64\), so \(√53\) is between 7 and 8. -
Estimate between two whole numbers:
Since \(49 < 53 < 64\), we confirm that \(√53\) lies between 7 and 8. -
Determine the closer whole number:
Since \(53\) is closer to \(49\) than to \(64\), \(√53\) is closer to \(7\). -
Find the squares of tenths:
- \(7.1^2 = 50.41\)
- \(7.2^2 = 51.84\)
- \(7.3^2 = 53.29\) (this is more than 53)
- \(7.4^2 = 54.76\)
Putting this together, we find that \(√53\) lies between \(7.2\) (which gives us \(51.84\)) and \(7.3\) (which gives us \(53.29\)).
Thus, the estimate can be concluded as:
√53 lies between 7.2 and 7.3.