Is the final term
1/(cotB-cotA) or
(1/cotB)-cotA ??
Is the numerator term (cotA cotB +1) or 1 ?
When you write equations like that, we can't tell what you mean.
I suggest you start with the identities for cos (A-B) and sin (A-B) and take the ratio of the two.
establish the identity:
cot(A-B)= cotAcotB+1/cotB-cotA
thanks for any help at all
2 answers
cos(a+b)/sin(a+b)=
cosacosb+sinasinb/sinacosb-cosasinb
multiplying and dividing by sinasins then it becomes
cotacotb+1/cotb-cota
cosacosb+sinasinb/sinacosb-cosasinb
multiplying and dividing by sinasins then it becomes
cotacotb+1/cotb-cota