Essay
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It is the same distance from second base to first base, and from second base to third base. The angle formed by first base, second base, and home plate has the same measure as the angle formed by third base, second base, and home plate. What can you conclude about the distance from first base to home plate, and from home plate to third base? Explain using your knowledge of congruent triangles.
The image of a baseball diamond is shown. The diamond itself is a square rotated so that a vertex is on the bottom. The bottom vertex is labeled 'Home,' the right vertex is labeled 'First,' the top vertex is labeled 'Second,' and the left vertex is labeled 'Third.' There is a diagonal drawn connecting 'Second' and 'Home.'
(6 points)
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1 answer
To explain this using our knowledge of congruent triangles, let's examine the geometry of the baseball diamond.
First, we know that the distance from second base to first base is equal to the distance from second base to third base. This means that we have two congruent sides in both triangles formed by second base, first base, and home plate, as well as second base, third base, and home plate.
Now, let's look at the angles. The angle formed by first base, second base, and home plate is congruent to the angle formed by third base, second base, and home plate. Since both triangles share a congruent angle and two congruent sides, they must be congruent triangles.
In congruent triangles, all corresponding sides and angles are congruent. Therefore, if the distance from second base to first base is equal to the distance from second base to third base, and the angles formed by both bases and home plate are congruent, then the distance from first base to home plate must be equal to the distance from home plate to third base.
In conclusion, based on the congruent triangles formed by the angles and sides of the baseball diamond, we can conclude that the distance from first base to home plate is equal to the distance from home plate to third base.