In a parallelogram, opposite sides are congruent. Therefore, we can set up equations based on the given side lengths.
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Set up equations for the sides:
\[ AB = CD \quad \text{and} \quad BC = AD \]
From the problem, we have:
- \( AB = 40x \)
- \( CD = 8x + 32 \)
- \( BC = 4 + 3y \)
- \( AD = 9y - 20 \)
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First equation (AB = CD):
\[ 40x = 8x + 32 \]
Rearranging gives:
\[ 40x - 8x = 32 \]
\[ 32x = 32 \]
\[ x = 1 \]
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Second equation (BC = AD):
Now, substitute \( x = 1 \) into the second equation:
\[ 4 + 3y = 9y - 20 \]
Rearranging this gives:
\[ 4 + 20 = 9y - 3y \]
\[ 24 = 6y \]
\[ y = 4 \]
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Final Answer:
- The value of \( x \) is \( 1 \).
- The value of \( y \) is \( 4 \).
To recap:
- The value of \( x \) is \( 1 \).
- The value of \( y \) is \( 4 \).