carbon dioxide collide with the liquid solvent and enters its dissolved states?
so what does this have to do with solubility equillibrium.
Equillibrium, an example given by my textbook confused me.
First it shows a reaction inside a soft drink: co2(g)--><--co2(aq)
but than it says the reaction inside a soft drink would involve solubility equillibrium because it involves a change in solubility between solvent h20(l) and solute co2(g).
I did not think this reaction was solubility equillibrium, because there is no crystalization or dissolving. However, carbon dioxide is entering and leaving the dissolved state at the same rate so how can this be solubility equillibrium
3 answers
does changes in solubility between solute and solvent, just mean that the rate at which solute co2(gas) is dissolved by solvent to form co2(aq) is = to rate at which c02(aq) gains eenrgy from collitions to leave dissolved state or what?
I need siome clarity.
I need siome clarity.
Your last paragraph: correct.