Equilibrium expression: AgCl(s) ⇌ Ag+(aq) + Cl-(aq) KSP = 1.8 x 10-10 The solubility of AgCl in: i) pure water: solubility = 1.3 x 10-5 M

Question

ii) a 0.50 M NaCl solution solubility = 3.6 x 10-10 M as KSP = [Ag+][Cl-]Total where [Cl-]Total = [Cl-]AgCl + [Cl-]NaCl

Answer 1

Equilibrium expression: AgCl(s) ⇌ Ag+(aq) + Cl-(aq) KSP = 1.8 x 10-10 The solubility of AgCl in: i) pure water: solubility = 1.3 x 10-5 M
ii) a 0.50 M NaCl solution solubility = 3.6 x 10-10 M as KSP = [Ag+][Cl-]Total where [Cl-]Total = [Cl-]AgCl + [Cl-]NaCl

I agree with 1.3E-5M for the solubility of AgCl in pure water.
Also I agree with 3.6E-10 M for the solubility of AgCl in 0.5M NaCl but nothing you posted after 3.6E-10 makes sense to me. You don't have a question; I assume you just want an answer check.