Equilateral triangle ABC and isosceles triangle DBC share side BC. If angle BDC= 34 and BD=BC, what is the measure of angle ABD?

Question

I don't know how to solve this questions, can someone guide me through?

Answer 1

All angles in the equilateral triangle are 60°
In the isosceles triangle the two base angles are
73 ° each ......... ( (180-34)/2 )

so angle ABD = 60+73 or 133°

Answer 2

Start by drawing a diagram.

If BC=BD, then
∠BDC=∠BCD=34° (angles opposite equal sides.

Hence ∠CBD=180-(34+34)=112°
∠ABD=∠ABC+∠CBD=?

Recall that ΔABC is equilateral.

Answer 3

Go with MathMate, I misread the question