To convert the equation π¦ = 3π₯^2 + 4 into vertex form, we need to complete the square.
Firstly, we factor the coefficient of x^2 out of the equation, which gives us:
π¦ = 3(x^2 + 4/3)
Next, we need to add and subtract a constant term to the parenthetical expression inside the parentheses. We can do this by taking half of the coefficient of x (which is 0 in this case) and squaring it.
(0/2)^2 = 0
So we add and subtract 0 inside the parentheses:
π¦ = 3(x^2 + 4/3 + 0 - 0)
Now we can write this expression in vertex form by factoring the perfect square inside the parentheses and applying the distributive property:
π¦ = 3((x + 0)^2 + 4/3 - 0)
Simplifying this expression gives us:
π¦ = 3(x + 0)^2 + 4
Therefore, the vertex of this equation is (0,4).
Equation in
vertex formπ = πππ + 4 find the Coordinates of
vertex
1 answer