To find the ratios for sin X and cos X, we first need to find the lengths of the sides of the triangle. Using the Pythagorean theorem, we can find the length of side YZ:
YZ^2 = XY^2 + XZ^2
YZ^2 = 12^2 + 5^2
YZ^2 = 144 + 25
YZ^2 = 169
YZ = sqrt(169)
YZ = 13
Now that we have all three side lengths, we can find the values of sin X and cos X:
sin X = opposite/hypotenuse = YZ/XY = 13/12
cos X = adjacent/hypotenuse = XZ/XY = 5/12
Therefore, the ratios for sin X and cos X are sin X = 13/12 and cos X = 5/12.
: Enter your answer and show all the steps that you use to solve this problem in the space provided.
Write the ratios for sin X
and cos X
.
Right triangle XYZ with right angle Z is shown. XY is labeled 12. XZ is labeled 5. YZ is labeled start root 119 end root.
(2 points)
1 answer