Enter > or < to make this statement true: 6/5⋅9/2

__ 6/5
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1 answer

To determine the relationship between \( \frac{6}{5} \cdot \frac{9}{2} \) and \( \frac{6}{5} \), we first need to calculate \( \frac{6}{5} \cdot \frac{9}{2} \).

Calculating:

\[ \frac{6}{5} \cdot \frac{9}{2} = \frac{6 \cdot 9}{5 \cdot 2} = \frac{54}{10} = \frac{27}{5} \]

Now, we need to compare \( \frac{27}{5} \) and \( \frac{6}{5} \):

Since both fractions are over the same denominator of 5, we can compare the numerators directly:

\[ 27 \quad \text{and} \quad 6 \]

Clearly, \( 27 > 6 \).

Thus,

\[ \frac{27}{5} > \frac{6}{5} \]

So the correct symbol is:

\[ \frac{6}{5} \cdot \frac{9}{2} , > , \frac{6}{5} \]

The final statement is:

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