To find the y-values for the equation \( y = \frac{1}{4}x + 2 \), you can plug in various x-values into the equation. Here are some example x-values and their corresponding y-values:
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If \( x = 0 \): \[ y = \frac{1}{4}(0) + 2 = 2 \]
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If \( x = 4 \): \[ y = \frac{1}{4}(4) + 2 = 1 + 2 = 3 \]
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If \( x = 8 \): \[ y = \frac{1}{4}(8) + 2 = 2 + 2 = 4 \]
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If \( x = 12 \): \[ y = \frac{1}{4}(12) + 2 = 3 + 2 = 5 \]
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If \( x = 16 \): \[ y = \frac{1}{4}(16) + 2 = 4 + 2 = 6 \]
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If \( x = -4 \): \[ y = \frac{1}{4}(-4) + 2 = -1 + 2 = 1 \]
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If \( x = -8 \): \[ y = \frac{1}{4}(-8) + 2 = -2 + 2 = 0 \]
You can choose any other x-values and use the formula to calculate the corresponding y-values. If you have specific x-values in mind, please share them, and I can help calculate the corresponding y-values!