To find the acceleration of the object, we can use the equation of motion:
v^2 = u^2 + 2as
where:
v = final velocity = 3.5 km/s = 3500 m/s
u = initial velocity = 0 m/s (object starting at rest)
a = acceleration
s = displacement = 0.02 m
Plugging in the values, we get:
(3500)^2 = (0)^2 + 2 * a * 0.02
12250000 = 0.04a
a = 306250 m/s^2
So, the acceleration the gun gives the object is 306250 m/s^2.
To find the time interval, we can use the equation:
v = u + at
Plugging in the values we have:
3500 = 0 + 306250 * t
t = 0.01147 seconds
Therefore, the gun gives the object an acceleration of 306250 m/s^2 over a time interval of 0.01147 seconds.
engineers are developing new types of guns that might someday be used to launch satellites as if they were bullets. one such gun can give a small object starting at rest a velocity of 3.5km/s moving it through only 2.0cm
what acceleration does the gun give this object
over what time interval does this take place
1 answer