Asked by Paul
Engineers and physicists are fond of using the approximation Square root (1+x) = 1+(x/2)?
What approximation do you suppose the engineers and physicists would use for the quantity (1+x)^(3/2)
What approximation do you suppose the engineers and physicists would use for the quantity (1+x)^(3/2)
Answers
Answered by
drwls
The approximation is only good when x is much less than 1.
It is obtained from the Taylor series rule
f(x) = f(0) + f'(0) * x
= 1 + (3/2)*(1+x)^(1/2)*x + ...
(evaluated at x=0)
= 1 + (3/2)x
It is obtained from the Taylor series rule
f(x) = f(0) + f'(0) * x
= 1 + (3/2)*(1+x)^(1/2)*x + ...
(evaluated at x=0)
= 1 + (3/2)x
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.