mols Mg = mass Mg/atomic mass Mg.
Wouldn't mass Mg be (mass xble+Mg) - (mass empty xble)?
Now think about the MgO. Now that you see how easy it is to get mass Mg, wouldn't a very similar tactic obtain mass MgO.
empty cruble-34.69g
crucible+ magnesium- 34.86g
crucible+magnesium oxide - 34.97g
How can i find the number of moles of magnesium present at the start of the reaction
How can i also find the total number of magnesium oxide molecules present at the end of the reaction
1 answer
1 answer