Emma has $26 for her weekend expenses. She spent $12.81, including tax, on a new book. Additionally, she needs to set aside $10.00 for a lunch outing next week. If stickers cost $0.42 per package, tax included, describe the maximum number of packages (p) Emma can buy. (1 point)

Question

OP<7
Op<8
Op=7
Op≥8

Answer 1

To figure out the maximum number of packages that Emma can buy, we need to subtract her expenses from her total budget.

First, subtract the cost of the book: $26 - $12.81 = $<<26-12.81=13.19>>13.19

Next, subtract the amount she needs to set aside for lunch: $13.19 - $10.00 = $<<13.19-10=3.19>>3.19

Now, divide the remaining amount by the cost of one package of stickers: $3.19 ÷ $0.42 = <<3.19/0.42=7.60>>7.60

Since Emma cannot purchase a fraction of a package, the maximum number of sticker packages she can buy is 7. Answer: Op<8

Answer 2

Sam starts the summer with $950 in his wallet. He aims to have a minimum of $600 left by the end of the summer. Each week, he spends $35 on recreational activities. Write an inequality to determine the number of weeks Sam can continue spending money, and solve the inequality. (1 point)
• 950 + 35w > 600; w ≥ 11
• 950 - 35w ≥ 600; w ≤ 11
• 950 + 35w ≥ 600; w ≥ 10
• 950 - 35w ≥ 600; w ≤ 10

Answer 3

We need to write an inequality to determine the number of weeks Sam can continue spending money.

Since Sam starts with $950 and spends $35 each week, the inequality will be: 950 - 35w ≥ 600.

Now let's solve the inequality.

Subtract 950 from both sides: -35w ≥ -350.

Divide both sides by -35 (remember to reverse the inequality when dividing by a negative number): w ≤ 10.

The solution to the inequality is w ≤ 10.

So, the correct option is: 950 - 35w ≥ 600; w ≤ 10.

Answer 4

As a salesperson, you are paid $100 per week plus $3 per sale. This week you want your pay to be at least $160. Write and solve an inequality for the number of sales you need to make. (1 point)
• 100 — 3s ≤ 160; s ≤ 18
• 100 + 3s ≥ 160; s ≥ 20
• 100 + 3s ≥ 160; s ≥ 18
• 100 — 3s ≤ 160; s ≤ 20

Answer 5

We need to write an inequality for the number of sales needed to earn at least $160.

Since the salesperson is paid $100 per week plus $3 per sale, the inequality will be: 100 + 3s ≥ 160.

Now let's solve the inequality.

Subtract 100 from both sides: 3s ≥ 60.

Divide both sides by 3: s ≥ 20.

The solution to the inequality is s ≥ 20.

So, the correct option is: 100 + 3s ≥ 160; s ≥ 20.

Answer 6

An online music club has a one-time registration fee of $20 and charges $0.50 for each song download. If Ella has $50.00 to join the club and buy songs, which inequality gives the maximum number of songs, s, she can buy? (1 point)
O s ≥ 30
Os≤ 30
Os ≥ 60
Os< 60

Answer 7

To find the maximum number of songs Ella can buy, we need to set up an inequality using the information provided.

Ella has $50 to join the club and buy songs. She has to pay a registration fee of $20, so she has $50 - $20 = $30 left to spend on song downloads.

Each song download costs $0.50. Let's represent the maximum number of songs Ella can buy with the variable s.

Therefore, the inequality is: $0.50s ≤ $30.

Simplifying the inequality, we have: s ≤ 60.

So, Ella can buy a maximum of 60 songs. The correct inequality is Os ≤ 60.

Answer 8

Mark and Anson each have a video game collection.
• The number of video games in Mark collection can be represented by x.
• The number of video games in Anson collection is 5 times the number in Mark collection.
• The total number of video games is no more than 72.
What is the solution set for x, the number of video games in Mark's collection?
(1 point)
0 x ≤12
• x ≤-12
• x ≥ 15
Ox ≥-1

Answer 9

Let's represent the number of video games in Mark's collection as x.

According to the information provided, the number of video games in Anson's collection is 5 times the number in Mark's collection:
Anson's video games = 5x.

The total number of video games is no more than 72:
x + Anson's video games ≤ 72.

Substituting Anson's video games with 5x, we have:
x + 5x ≤ 72.

Combining like terms, we get:
6x ≤ 72.

To solve for x, we divide both sides of the inequality by 6:
x ≤ 12.

Therefore, the solution set for x, the number of video games in Mark's collection, is x ≤ 12.
The correct option is: 0 ≤ x ≤ 12.

Answer 10

Our middle school is having a fall carnival. Admission into the carnival is $3 and each game inside the carnival costs $.25. Write an inequality that represents the possible number of games that can be played having $10.
What is the maximum number of games that can be played? (1 point)
• 0.25z +3 ≤ 10;28 games
• 0.25x — 3 ≤ 10; 52 games
• 0.25x - 3 < 10; 52 games
• 0.25x + 3 < 10; 28 games

Answer 11

To represent the possible number of games that can be played with $10, we'll use the inequality $0.25x + 3 ≤ 10, where x represents the number of games.

Now, let's solve the inequality to find the maximum number of games that can be played.

Subtract 3 from both sides: $0.25x ≤ 7.

To isolate x, divide both sides by $0.25: x ≤ 28.

Therefore, the maximum number of games that can be played with $10 is 28.

The correct option is: $0.25z +3 ≤ 10; 28 games.