mgh=1/2 m v^2
solve for v
Emily holds a banana of mass m over the edge of a bridge of height h. She drops the banana and it falls to the river below. Use conservation of energy to find the speed of the banana just before hitting the water.Express your answer in terms of some or all of the variables h and m, and appropriate constants.
5 answers
2gh
v= the square root of 2gh
V^2/g = h
GPE=mgh & KE=1/2m(v^2)
-In this equation potential becomes kinetic-
mgh=1/2m(v^2) [divide both sides by mass so it cancels]
->
mh=1/2(v^2) [divide both sides by 0.5 which is 1/2 so it cancels]
->
2mh=v^2 [find root of both sides so square of v cancels]
->
Square root of (2mh) = velocity
-In this equation potential becomes kinetic-
mgh=1/2m(v^2) [divide both sides by mass so it cancels]
->
mh=1/2(v^2) [divide both sides by 0.5 which is 1/2 so it cancels]
->
2mh=v^2 [find root of both sides so square of v cancels]
->
Square root of (2mh) = velocity